#include
void e(int n)
{
if(n>0)
{
e(--n);
printf("%d",6*n*6);
e(--n);
}
}
int main()
{
e(4);
}
--Asked by Koole Keshava
Thursday, 8 May 2008
what is the output of this program?
what is the output of this program ???explain plzzz
#include
void e(int n)
{
if(n>0)
{
e(--n);
printf("%d",6*n*6);
e(--n);
}
}
int main()
{
e(4);
}
--Asked by Koole Keshava
#include
void e(int n)
{
if(n>0)
{
e(--n);
printf("%d",6*n*6);
e(--n);
}
}
int main()
{
e(4);
}
--Asked by Koole Keshava
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1 comment:
nothing will n printed?
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